Now, h = -b/2a. Plug in the values into the formula, and you get: The parabola's axis of symmetry (x = h) is a vertical line passing through the vertex, so as demonstrated above, this is x = 1.

Find the equation of the line of symmetry and the coordinates of the turning point of the graph of \(y = x^2 – 6x + 4\) The coefficient of \(x^2\) is positive, so the graph will be a positive U ...

Find the equation of the line of symmetry and the coordinates of the turning point of the graph of \(y = x^2 - 6x + 4\). Writing \(y = x^2 - 6x + 4 \) in completed square form gives \(y = (x - 3 ...